Scrape job listings with our Google Jobs API

import requests

headers = {"apikey": "your-apikey"}
params = {
    "q": "backend engineer",
    "tbm": "jobs",
    "location": "Austin,Texas,United States",
}

response = requests.get(
    "https://app.zenserp.com/api/v2/search",
    headers=headers,
    params=params,
)
data = response.json()

for j in data["jobs"]:
    print(j["title"], j["company"], j["location"])

const axios = require("axios");

axios.get("https://app.zenserp.com/api/v2/search", {
  headers: { apikey: "your-apikey" },
  params: {
    q: "backend engineer",
    tbm: "jobs",
    location: "Austin,Texas,United States",
  },
}).then(({ data }) => {
  data.jobs.forEach((j) => console.log(j.title, j.company, j.location));
});

<?php
$params = http_build_query([
    "q" => "backend engineer",
    "tbm" => "jobs",
    "location" => "Austin,Texas,United States",
]);

$ch = curl_init();
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_URL, "https://app.zenserp.com/api/v2/search?" . $params);
curl_setopt($ch, CURLOPT_HTTPHEADER, ["apikey: your-apikey"]);

$data = json_decode(curl_exec($ch), true);
curl_close($ch);

foreach ($data["jobs"] as $j) {
    echo $j["title"] . " " . $j["company"] . " " . $j["location"] . PHP_EOL;
}